SQL 查询和删除重复字段数据的技巧
发布时间：2021-11-26 16:02:12 所属栏目：教程 来源：互联网
导读：例如： id name value 1 a pp 2 a pp 3 b iii 4 b pp 5 b pp 6 c pp 7 c pp 8 c iii id是主键 要求得到这样的结果 id name value 1 a pp 3 b iii 4 b pp 6 c pp 8 c iii 方法1 复制代码 代码如下: delete YourTable where [id] not in ( select max([id]) fr
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例如： id name value 1 a pp 2 a pp 3 b iii 4 b pp 5 b pp 6 c pp 7 c pp 8 c iii id是主键 要求得到这样的结果 id name value 1 a pp 3 b iii 4 b pp 6 c pp 8 c iii 方法1 复制代码 代码如下: delete YourTable where [id] not in ( select max([id]) from YourTable group by (name + value)) 方法2 复制代码 代码如下: delete a from 表 a left join( select id=min(id) from 表 group by name,value )b on a.id=b.id where b.id is null 查询及删除重复记录的SQL语句 查询及删除重复记录的SQL语句 1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断 复制代码 代码如下: select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录 复制代码 代码如下: delete from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1) 3、查找表中多余的重复记录（多个字段） 复制代码 代码如下: select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) 4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录 复制代码 代码如下: delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) 5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录  （编辑：我爱制作网_潮州站长网） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |
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